关于自学SQL的语句集合

Table(表）: Movies

Id	Title	Director	Year	Length_minutes
1	Toy Story	John Lasseter	1995	81
2	A Bug's Life	John Lasseter	1998	95
3	Toy Story 2	John Lasseter	1999	93
4	Monsters, Inc.	Pete Docter	2001	92
5	Finding Nemo	Finding Nemo	2003	107
6	The Incredibles	Brad Bird	2004	116
7	Cars	John Lasseter	2006	117
8	Ratatouille	Brad Bird	2007	115
9	WALL-E	Andrew Stanton	2008	104
10	Up	Pete Docter	2009	101
11	Toy Story 3	Lee Unkrich	2010	103
12	Cars 2	John Lasseter	2011	120
13	Brave	Brenda Chapman	2012	102
14	Monsters University	Dan Scanlon	2013	110

 SQL Lesson 1: SELECT 查询 101

1.找到所有电影的名称title

SELECT title FROM movies;

2.找到所有电影的导演

SELECT director FROM movies;

3.找到所有电影的名称和导演

SELECT title,director FROM movies;

4.找到所有电影的名称和上映年份

SELECT title,year FROM movies;

5.找到所有电影的所有信息

SELECT * FROM movies;

6.找到所有电影的名称,Id和播放时长

SELECT id,title,length_minutes FROM movies;

SQL Lesson 2: 条件查询 (constraints) (Pt. 1)

1.找到id为6的电影

SELECT * FROM movies where id='6';

2.找到在2000-2010年间year上映的电影

SELECT * FROM movies where year between '2000' and '2010';

3.找到不是在2000-2010年间year上映的电影

SELECT * FROM movies where year not between '2000' and '2010';

4.找到头5部电影

SELECT * FROM movies where id<='5';

5.找到2010（含）年之后的电影里片长小于两个小时的片子

SELECT * FROM movies where year>='2010' and length_minutes<'120';

SQL Lesson 3: 条件查询(constraints) (Pt. 2)

1.找到所有Toy Story系列电影

SELECT * FROM movies where title like 'Toy Story%';

2.找到所有John Lasseter导演的电影

SELECT * FROM movies where director='John Lasseter';

3.找到所有不是John Lasseter导演的电影

SELECT * FROM movies where director!='John Lasseter';

4.找到所有电影名为 "WALL-" 开头的电影

SELECT * FROM movies where title like 'WALL-%';

5.有一部98年电影中文名《虫虫危机》请给我找出来

SELECT * FROM movies where year like '%98';

SQL Lesson 4: 查询结果Filtering过滤 和 sorting排序

1.按导演名排重列出所有电影(只显示导演)，并按导演名正序排列

SELECT distinct director FROM movies order by director asc;

2.列出按上映年份最新上线的4部电影

SELECT * FROM movies order by year desc limit 4;

3.按电影名字母序升序排列，列出前5部电影

SELECT * FROM movies order by title asc limit 5;

4.按电影名字母序升序排列，列出上一题之后的5部电影

SELECT * FROM movies order by title asc limit 5 offset 5;

5.如果按片长排列，John Lasseter导演导过片长第3长的电影是哪部，列出名字即可

SELECT title FROM movies where director='John Lasseter'
order by length_minutes desc limit 1 offset 2;

SQL Review: 复习 SELECT 查询

1.列出所有加拿大人的Canadian信息(包括所有字段)

SELECT * FROM north_american_cities where country='Canada';

2.列出所有在Chicago西部的城市，从西到东排序(包括所有字段)

SELECT * FROM north_american_cities where longitude<(select longitude
FROM north_american_cities where city='Chicago')
order by longitude asc;

3.用人口数population排序,列出墨西哥Mexico最大的2个城市(包括所有字段)

select * from North_american_cities where country='Mexico'
order by population desc
limit 2;

4.列出美国United States人口3-4位的两个城市和他们的人口(包括所有字段)

select * from North_american_cities where country='United States'
order by population desc
limit 2 offset 2;

SQL Lesson 6: 用JOINs进行多表联合查询

1.找到所有电影的国内Domestic_sales和国际销售额

SELECT * FROM movies a
inner join Boxoffice b on b.movie_id=a.id;

2.找到所有国际销售额比国内销售大的电影

SELECT * FROM movies a
inner join Boxoffice b on b.movie_id=a.id and b.international_sales>b.domestic_sales;

3.找出所有电影按市场占有率rating倒序排列

SELECT * FROM movies a
inner join Boxoffice b on b.movie_id=a.id
order by rating desc;

4.每部电影按国际销售额比较,排名最靠前的导演是谁,国际销量多少

SELECT director,international_sales FROM movies a
inner join Boxoffice b on b.movie_id=a.id
order by international_sales desc
limit 1;

延伸：查找国际销售额最多的导演和销量

SELECT director,sum(international_sales) as international_sales FROM movies a
inner join Boxoffice b on b.movie_id=a.id
group by director
order by international_sales desc
limit 1;

SQL Lesson 7: 外连接（OUTER JOINs）

1.找到所有有雇员的办公室(buildings)名字

SELECT distinct a.building_name FROM Buildings a 
left join employees b on b.building=a.building_name
where building is not null;

2.找到所有办公室里的所有角色（包含没有雇员的）,并做唯一输出(DISTINCT)

SELECT distinct a.building_name,b.role FROM Buildings a 
left join employees b on b.building=a.building_name;

3.找到所有有雇员的办公室(buildings)和对应的容量

SELECT distinct a.building_name,a.capacity FROM Buildings a 
left join employees b on b.building=a.building_name
where role is not null;