UVA 562 - Dividing coins

考虑全面，01背包问题：

代码如下：

#include<string.h>
#include<stdio.h>
#include<stdlib.h>
#define MAXN 100 + 5
#define MAXN1 25000 + 100
int coin[MAXN], f[MAXN][MAXN1];
int n, m, sum, c;
/*int cmp(const void* _p, const void* _q)
{
    int *p = (int *)_p;
    int *q = (int *)_q;
    return *p - *q;
}*/
void dp()
{
    int i, j, k;
    memset(f, 0, sizeof(f));
    /*for(i = 1; i <= m; i ++)
    {
        if(coin[i]>c) break;
        for(j = coin[i]; j <= c; j ++)
        {
            if(f[i-1][j] < f[i-1][j-coin[i]]+coin[i])
                f[i][j] = f[i-1][j-coin[i]]+coin[i];
            else f[i][j] = f[i-1][j];
        }
    }*/
    for(i = 1; i <= m; i ++)
        for(j = 0; j <= c; j ++)
        {
            f[i][j] = f[i - 1][j];
            if(j >= coin[i] && (k = f[i - 1][j - coin[i]] + coin[i]) > f[i][j])    
                f[i][j] = k;
        }
    printf("%d\n",sum-2*f[m][c]);
}
void input()
{
    while(scanf("%d",&n) == 1)
    {
        while(n --)
        {
            sum = 0;
            scanf("%d",&m);
            for(int i = 1; i <= m; i ++)
            {
                scanf("%d",&coin[i]);
                sum += coin[i];
            }
            c = sum / 2;
            //qsort(coin + 1, m, sizeof(coin[0]), cmp);
            dp();
        }
    }
}
int main()
{
    input();
    return 0;
}