TreeView(递归)

很简单,不多说
最终效果:
TreeView(递归)
数据库(Access):

代码:

< html  xmlns ="http://www.w3.org/1999/xhtml"   >
< head  runat ="server" >
    
< title > 无标题页 </ title >
</ head >
< body >
    
< form  id ="form1"  runat ="server" >
        
< div  style ="text-align:center;" >
            
< div  style ="margin:5px; float:left;" >< asp:TreeView  runat ="server"  ID ="Tree1" ></ asp:TreeView ></ div >
            
< div  style ="margin-left:12px;" >< asp:GridView  runat ="server"  ID ="GridView1" ></ asp:GridView ></ div >
        
</ div >  
    
</ form >
</ body >
</ html >

public   partial   class  InfoSort : System.Web.UI.Page
    
{
        DataSet ds 
= null;
        
protected void Page_Load(object sender, EventArgs e)
        
{
            
if (!IsPostBack)
            
{
                BindData();
                loadtree();
            }

        }

        
private void loadtree()
        
{
            Tree1.Nodes.Clear();
            ds 
= GetDataSet("SELECT * FROM sort");
            InitTree(Tree1.Nodes, 
0);
        }

        
private void InitTree(TreeNodeCollection Nds,int parentid)
        
{
            DataView dv 
= new DataView();
            TreeNode tmpNd 
= null;
            dv.Table 
= ds.Tables[0];
            dv.RowFilter 
= String.Format("parentid={0}", parentid);
            
foreach (DataRowView drv in dv)
            
{
                tmpNd 
= new TreeNode();
                tmpNd.Text 
= (string)drv["sortname"];//节点名称
                tmpNd.NavigateUrl = String.Format("?id={0}", drv["id"]);//节点URL
                
//tmpNd.ImageUrl = ""; //节点图片
                if (parentid == 0)
                    tmpNd.Expanded 
= true;
                
else
                    tmpNd.Expanded 
= false;
                Nds.Add(tmpNd);
                InitTree(Nds[Nds.Count 
- 1].ChildNodes, (int)drv["id"]);
            }

        }

        
private void BindData()
        
{
            GridView1.DataSource 
= GetDataSet("select * from sort");
            GridView1.DataBind();
        }


        
Dal
    }

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