JS力扣刷题 122. 买卖股票的最佳时机 II

var maxProfit = function(prices) {
    //当天赚当天抛，永远不亏
    let res = 0;
    for(let i = 1; i < prices.length; i++)
        if(prices[i] - prices[i - 1] > 0)res += prices[i] - prices[i - 1];
    return res;
};