我的第一道java_A+B

JAVA——A+B

——————我的第一道JAVA

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 241566    Accepted Submission(s): 46567

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

 

Sample Input

2 1 2 112233445566778899 998877665544332211

 

 

Sample Output

Case 1:

1 + 2 = 3

Case 2:

112233445566778899 + 998877665544332211 = 1111111111111111110

 

 大数题，我的第一道JAVA

 

import java.util.Scanner;

import java.math.BigInteger;



public class Main {

    final int maxn=1000100;

    public static void main(String[] args){

        Scanner in=new Scanner(System.in);

        int T;

        T=in.nextInt();

        for(int i=1;i<=T;i++){

            BigInteger a,b,c;

            a=in.nextBigInteger();

            b=in.nextBigInteger();

            c=a.add(b);

            System.out.println("Case "+i+":");

            System.out.println(a.toString()+" + "+b.toString()+" = "+c.toString());

            if(i<T) System.out.println();

        }

    }

}

A+B