每日一shell-字符串分割-2020-05-14

llinux查看样本为单端测序还是双端测序：

# cat findfile.test.sh
samples=$(for i in $(ls *_R1*.fastq.gz);do echo "${i%%_*}";done)

for ID in $samples
do
    if [ -f ${ID}*R2*fastq.gz ];then
        echo PE ${ID}*R1*fastq.gz ${ID}*R2*fastq.gz
    else
        echo SE ${ID}*R1*fastq.gz
    fi
done

分隔文件名称，去除扩展名，得到样本名称列表：

sh findfile.test.sh | grep PE | awk '{print $2}' | awk '{split($0,a,"_");print a[1]}' > PE.files.txt
sh findfile.test.sh | grep SE | awk '{print $2}' | awk '{split($0,a,"_");print a[1]}' > SE.files.txt