最小生成树,由于是special judge 所以不用非得结果和样例一样
#include < iostream >
#include < cstdio >
#include < cstdlib >
#include < cstring >
#include < algorithm >
using namespace std;
#define maxm 15005
#define maxn 1005
struct Edge
{
int u, v, w;
}edge[maxm], mst[maxm];
int n, m, ecount, father[maxn];
void input()
{
scanf( " %d%d " , & n, & m);
for ( int i = 0 ; i < m; i ++ )
scanf( " %d%d%d " , & edge[i].u, & edge[i].v, & edge[i].w);
}
bool operator < ( const Edge & a, const Edge & b)
{
return a.w < b.w;
}
int getanc( int a)
{
if (father[a] == a)
return a;
return father[a] = getanc(father[a]);
}
void merge( int a, int b)
{
father[getanc(a)] = getanc(b);
}
void work()
{
for ( int i = 1 ; i <= n; i ++ )
father[i] = i;
int ans;
ecount = 0 ;
for ( int i = 0 ; i < m; i ++ )
if (getanc(edge[i].u) != getanc(edge[i].v))
{
merge(edge[i].u, edge[i].v);
ans = edge[i].w;
mst[ecount ++ ] = edge[i];
}
printf( " %d\n%d\n " , ans, ecount);
for ( int i = 0 ; i < ecount; i ++ )
printf( " %d %d\n " , mst[i].u, mst[i].v);
}
int main()
{
// freopen("t.txt", "r", stdin);
input();
sort(edge, edge + m);
work();
return 0 ;
}