poj1005

简单题

View Code
#include <iostream>

#include <cmath>

using namespace std;



const    double    pi = 3.14159265;



int work()

{

    double    x, y, l;



    cin >> x;

    cin >> y;

    l = x * x + y * y;

    return int(l * pi / 100) + 1;

}



int main()

{

    int        n, t;



    //freopen("t.txt", "r", stdin);

    t = 0;

    cin >> n;

    while (n--)

    {

        t++;

        printf("Property %d: This property will begin eroding in year %d.\n", t, work());

    }

    cout << "END OF OUTPUT." << endl;

    return 0;

}

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