poj2363

简单题

打表， 打了之后的程序发布上来……

View Code

   
     

    
      #include 
    
      <
    
      iostream
    
      >
    
      
#include 
    
      <
    
      cstdio
    
      >
    
      
#include 
    
      <
    
      cstdlib
    
      >
    
      
#include 
    
      <
    
      cstring
    
      >
    
      

    
      using
    
       
    
      namespace
    
       std;


    
      int
    
       cal(
    
      int
    
       a, 
    
      int
    
       b, 
    
      int
    
       c)
{
 
    
      return
    
       (a 
    
      *
    
       b 
    
      +
    
       b 
    
      *
    
       c 
    
      +
    
       c 
    
      *
    
       a) 
    
      *
    
       
    
      2
    
      ;
}


    
      int
    
       work(
    
      int
    
       a)
{
 
    
      int
    
       ans 
    
      =
    
       
    
      1000000000
    
      ;
 
    
      for
    
       (
    
      int
    
       i 
    
      =
    
       
    
      1
    
      ; i 
    
      *
    
       i 
    
      *
    
       i 
    
      <=
    
       a; i
    
      ++
    
      )
 
    
      for
    
       (
    
      int
    
       j 
    
      =
    
       i; i 
    
      *
    
       j 
    
      *
    
       j 
    
      <=
    
       a; j
    
      ++
    
      )
 {
 
    
      int
    
       k 
    
      =
    
       a 
    
      /
    
       i 
    
      /
    
       j;
 
    
      if
    
       (i 
    
      *
    
       j 
    
      *
    
       k 
    
      ==
    
       a 
    
      &&
    
       cal(i, j, k) 
    
      <
    
       ans)
 ans 
    
      =
    
       cal(i, j, k);
 }
 
    
      return
    
       ans;
}


    
      int
    
       main()
{
 freopen(
    
      "
    
      t.txt
    
      "
    
      , 
    
      "
    
      w
    
      "
    
      , stdout);
 
    
      for
    
       (
    
      int
    
       i 
    
      =
    
       
    
      1
    
      ; i 
    
      <=
    
       
    
      1000
    
      ; i
    
      ++
    
      )
 {
 printf(
    
      "
    
      %d,
    
      "
    
      , work(i));
 }
 
    
      return
    
       
    
      0
    
      ;
}