Java TCP 程序

服务器采用BIO模式，每一个线程处理一个连接。问题出现在，如果使用BufferedReader去读取字符流，如果没有换行符的话，那么就会导致线程阻塞。因为调用了readLine()方法。

import java.io.*;

import java.net.Socket;

import java.net.InetAddress;

import java.net.ServerSocket;

import java.util.Scanner;



class ServerSocketTest {

	public static void main(String[] args) {

		try {

			ServerSocket ss = new ServerSocket(6000);

			System.out.println("Server running, waitting for client to login ...");

			Socket s = ss.accept();

			

			OutputStream os = s.getOutputStream();

			InputStream is = s.getInputStream();

			os.write("Hello Wellcome\n".getBytes());

			os.flush();

			

	

			/*

			byte[] buf = new byte[1024];

			int len = is.read(buf);

			System.out.println(new String(buf,0,len));*/

			

			BufferedReader br = new BufferedReader(new InputStreamReader(is));

			String line = null;

			while((line = br.readLine()) != null){

				System.out.println(line);

			}

			

			os.close();

			is.close();

			s.close();

			ss.close();



		} catch (Exception e) {

			e.printStackTrace();

		}

	}

}

 客户端程序。同样会阻塞，因为调用了readLine()方法。

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStream;

import java.io.InputStreamReader;

import java.io.OutputStream;

import java.io.PrintWriter;

import java.net.InetAddress;

import java.net.Socket;

import java.net.UnknownHostException;



public class SocketTest {

	public static void main(String[] args){

		try {

			System.out.println(InetAddress.getLocalHost());

			Socket s = new Socket(InetAddress.getLocalHost(), 6000);

			

			OutputStream os = s.getOutputStream();

			PrintWriter pw = new PrintWriter(os);

			pw.write("username:fangying;password:123\n");

			pw.flush();

			

			InputStream is = s.getInputStream();

			BufferedReader br = new BufferedReader(new InputStreamReader(is));

			String line = null;

			while ((line = br.readLine()) != null) {

				System.out.println("client get :" + line);

			}



			br.close();

			is.close();

			pw.close();

			os.close();

			s.close();

		} catch (Exception e) {

			e.printStackTrace();

		}

	}

}