FastJson的基本使用实践

序列化一个对象成为JSON字符串

        User user = new User();
        user.setName("小白");
        user.setAge(12);
        user.setEmail("[email protected]");

        String formarStr = JSON.toJSONString(user);
        KLog.d("输出信息--", formarStr);

        输出信息
        
        {"age":12,"email":"[email protected]","name":"小白"}

反序列化一个JSON字符串成为一个对象

        String jsonString = "{\"name\":\"小黑\",\"age\":20,\"email\":\"[email protected]\"}";
        User user1 = JSON.parseObject(jsonString,User.class);
        KLog.d("输出信息--", user1.toString());

        输出信息
        
        User{name='小黑', age=20, email='[email protected]'}

数组序列化成为JSON字符串

        List users = new ArrayList<>();
        users.add(user);
        users.add(user1);
        String userStr = JSON.toJSONString(users);
        KLog.d("输出信息-userStr-", userStr);
        
        输出信息
        
        [{"age":12,"email":"[email protected]","name":"小白"},{"age":20,"email":"[email protected]","name":"小黑"}]
        

JSON字符串反序列化为数组

        List user2 = JSON.parseArray(userStr,User.class);
        KLog.d("输出信息-user2.size()-", user2.size());
        
        输出信息
        
        2

序列化Map成为JSON字符串

        Map dataMap = new HashMap<>();
        dataMap.put("tag", "data");
        dataMap.put("hospitalName", "我是医院名字");
        dataMap.put("name", "欧阳夏凡");
        dataMap.put("gender", "女");
        dataMap.put("age", "28");
        dataMap.put("code", "420502042");
        dataMap.put("examineDoc", "杨林");
        dataMap.put("examineDate", "2016-05-10");
        dataMap.put("verifyDoc", "王菲");
        KLog.d("MapToJson-", JSON.toJSONString(dataMap));
        
        输出信息
        
         {"age":"28","code":"420502042","examineDate":"2016-05-10","examineDoc":"杨林","gender":"女","hospitalName":"我是医院名字","name":"欧阳夏凡","tag":"data","verifyDoc":"王菲"}

反序列化JSON字符串到Map

        Map dataMap = new HashMap<>();
        dataMap.put("tag", "data");
        dataMap.put("hospitalName", "我是医院名字");
        dataMap.put("name", "欧阳夏凡");
        dataMap.put("gender", "女");
        dataMap.put("age", "28");
        dataMap.put("code", "420502042");
        dataMap.put("examineDoc", "杨林");
        dataMap.put("examineDate", "2016-05-10");
        dataMap.put("verifyDoc", "王菲");
        KLog.d("MapToJson-", JSON.toJSONString(dataMap));
        Map maps =  JSON.parseObject(JSON.toJSONString(dataMap),Map.class);
        KLog.d("JsonToMap-",maps.toString());
        
        方法
        Map maps =  JSON.parseObject(JSON.toJSONString(dataMap),Map.class);
        
        输出结果
        
         {age=28, tag=data, examineDate=2016-05-10, verifyDoc=王菲, name=欧阳夏凡, gender=女, examineDoc=杨林, hospitalName=我是医院名字, code=420502042}

        

如果只想解析某个属性

        User user = new User();
        user.setName("小白");
        user.setAge(12);
        user.setEmail("[email protected]");
        SimplePropertyPreFilter filter = new SimplePropertyPreFilter(User.class, "name");
        String formarStr = JSON.toJSONString(user,filter);
        KLog.d("输出信息--", formarStr);
        
        输出结果
        
        {"name":"小白"}