https://www.nowcoder.com/practice/566f7f9d68c24691aa5abd8abefa798c?tpId=101&&tqId=33229&rp=3&ru=/activity/oj&qru=/ta/programmer-code-interview-guide/question-ranking
题目描述:输入一棵二叉树树,输入树的形式是每一行输入三个数,分别是节点value和左右孩子value。输出为树的先序、中序和后序遍历。
思路:首先根据输入的二叉树建树,然后进行先序、中序、后序遍历。
#include
#include
#include
#include
#include
using namespace std;
#define MAX_N 1000000
struct BinTree{
int data;
BinTree *lchild, *rchild;
} *root;
int n, N;
BinTree *CreateTree(int fa_index[][2], int value){
if(value==0) return NULL;
BinTree *p;
p = (BinTree *)malloc(sizeof(BinTree));
p->data = value;
p->lchild = CreateTree(fa_index, fa_index[value][0]);
p->rchild = CreateTree(fa_index, fa_index[value][1]);
return p;
}
// 先序遍历
void PreOrder(BinTree *head){
if(head){
N += 1;
if(N == n)
printf("%d\n", head->data);
else if(N < n)
printf("%d ", head->data);
PreOrder(head->lchild);
PreOrder(head->rchild);
}
}
//中序遍历
void InOrder(BinTree *head){
if(head){
InOrder(head->lchild);
N += 1;
if(N == n)
printf("%d\n", head->data);
else if(N < n)
printf("%d ", head->data);
InOrder(head->rchild);
}
}
//后序遍历
void PostOrder(BinTree *head){
if(head){
PostOrder(head->lchild);
PostOrder(head->rchild);
if(head->data==root->data)
printf("%d\n", head->data);
else
printf("%d ", head->data);
}
}
int main()
{
int fa_index[MAX_N+1][2], value; //前提是节点的value不重复
while(scanf("%d %d", &n, &value)!=EOF){
memset(fa_index, 0, sizeof(fa_index));
for(int i=0; i