poj3299
这一题学会了两个东西：
1.cmath中的exp(x)函数是用来求e的x次幂。
2.对于double类型scanf时要用%lf，printf时要用%f。
这个题就是个套公式的简单题
View Code
#include
<
iostream
>
#include
<
cstdlib
>
#include
<
cstdio
>
#include
<
cstring
>
#include
<
cmath
>
using
namespace
std;
int
getid(
char
*
st)
{
if
(strcmp(st,
"
T
"
)
==
0
)
return
0
;
if
(strcmp(st,
"
D
"
)
==
0
)
return
1
;
return
2
;
}
void
calt(
double
&
t,
double
&
d,
double
&
h)
{
double
e, hh;
e
=
6.11
*
exp((
5417.7530
*
((
1
/
273.16
)
-
(
1
/
(d
+
273.16
)))));
hh
=
(
0.5555
)
*
(e
-
10.0
);
t
=
h
-
hh;
}
void
cald(
double
&
t,
double
&
d,
double
&
h)
{
double
e, hh;
hh
=
h
-
t;
e
=
hh
/
0.5555
+
10.0
;
d
=
1
/
(
1
/
273.16
-
log(e
/
6.11
)
/
5417.7530
)
-
273.16
;
}
void
calh(
double
&
t,
double
&
d,
double
&
h)
{
double
e, hh;
e
=
6.11
*
exp((
5417.7530
*
((
1
/
273.16
)
-
(
1
/
(d
+
273.16
)))));
hh
=
(
0.5555
)
*
(e
-
10.0
);
h
=
t
+
hh;
}
int
main()
{
//
freopen("D:\\t.txt", "r", stdin);
char
st[
100
];
double
data[
3
];
while
(scanf(
"
%s
"
, st)
!=
EOF
&&
!
(strcmp(st,
"
E
"
)
==
0
))
{
data[
0
]
=
data[
1
]
=
data[
2
]
=
0
;
double
a;
scanf(
"
%lf
"
,
&
a);
data[getid(st)]
=
a;
scanf(
"
%s
"
, st);
scanf(
"
%lf
"
,
&
a);
data[getid(st)]
=
a;
getchar();
if
(data[
0
]
==
0
)
calt(data[
0
], data[
1
], data[
2
]);
if
(data[
1
]
==
0
)
cald(data[
0
], data[
1
], data[
2
]);
if
(data[
2
]
==
0
)
calh(data[
0
], data[
1
], data[
2
]);
printf(
"
T %.1f D %.1f H %.1f\n
"
, data[
0
], data[
1
], data[
2
]);
}
return
0
;
}