刷LeetCode(7)——Reverse Integer

刷LeetCode(7)——Reverse Integer

Code it now !https://leetcode.com/problems/reverse-integer/description/

Given a 32-bit signed integer, reverse digits of an integer.

Example 1:

Input: 123
Output:  321

Example 2:

Input: -123
Output: -321

Example 3:

Input: 120
Output: 21

Note:

Assume we are dealing with an environment which could only hold integers within the 32-bit signed integer range. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

解法:题目比较简单,没过多的考虑,实现如下:

class Solution {
     
public:
    int reverse(int x) {
        long long res = 0;
        while(x) {
            res = res*10 + x%10;
            x /= 10;
        }
        return (resINT_MAX) ? 0 : res;
    }
};

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