Leetcode 357. Count Numbers with Unique Digits[medium]

题目:
Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n.

Example:
Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99])


这题没什么好说的,排列组合。
唯一注意就是n=0输出1。

这里写图片描述

class Solution {
public:
    int countNumbersWithUniqueDigits(int n) {
        int rt = 0;
        if (n == 0) return 1;
        if (n > 10) n = 10;
        if (n >= 1) rt = 10;

        while (n > 1) {
            int ans = 0;
            int ans1 = 1;
            for (int i = 9; i >= 9 - n + 1; i--) ans1 *= i;
            ans += ans1;
            ans1 = n - 1;
            for (int i = 9; i >= 9 - n + 2; i--) ans1 *= i;
            ans += ans1;
            rt += ans;
            n--;
        }
        return rt;
    }
};

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