number(10,6)正则

	/**
	 * 判断number(10,6)
	 * @param dateStr
	 * @return
	 */
	public boolean isNumJW(String num){
		String regex = "^(\\d{0,4}\\.\\d{0,6})$";
		//符号需要转义,纯正则为:^(\d{0,4}\.\d{0,6})$
		Pattern p = Pattern.compile(regex);
		Matcher m = p.matcher(num);
		return m.matches();
	}