[leetcode-223]Rectangle Area(c++)

问题描述：
Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

分析：这道题的题意是获取两个矩形所覆盖的全面积，当然是两个矩形面积之和减去交叉矩形的面积，所以关键就变成了交叉面积咋求。说白了，还是求四个坐标值。

代码如下：３２ｍｓ

class Solution {
public:
    int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int row = abs(C-A);
        int col = abs(D-B);

        int area = row*col;
        row = abs(G-E);
        col = abs(H-F);
        area+=row*col;

        //int middle area
        int left = E>A?E:A;
        int right = Cif(rightreturn area;

        row = right-left;

        left = B>F?B:F;
        right = Hif(rightreturn area;

        col = right-left;
        if(row<0||col<0)
            return area;
        return area-row*col;
    }
};