理解C语言算法的实现，以三道题目为例

 

#include

int main()
{
    long i;
    int j;
    
    printf("Please input number:");
    scanf("%ld",&i);

    for(j=999;j>=100;j--)
    {
        if(i % j == 0)
        {
            printf("The max factor with 3digits in %ld is: %d\n",i,j);
            break;
        }
    }
    return 0;
}

 

 

 

 

#include

int main()
{
    int i, x, y, last=1;

    printf("Input X and Y (X * * Y):");
    scanf("%d %d", &x, &y);

    for(i == 1;i<=y;i++)
    {
        last = last * x %1000;
    }
    printf("The last 3 digits of %d * * %d is:%d\n", x, y, last%1000);
    return 0;
}

 

 

#include

int main()
{
    int a, count=0;
    for(a=5;a<=100;a+=5)
    {
        count++;
        if(!(a%25))
        {
            count++;
        }
    }
    printf("The number of 0 in the end of 100! is:%d.\n",count);
    return 0;
}