HttpRequest

stream发送请求

发送请求
            HttpWebRequest req = (HttpWebRequest)HttpWebRequest.Create(url4);

            req.Method = "POST";
byte[] bs = Encoding.GetEncoding("GB2312").GetBytes(json2);
            var stream = req.GetRequestStream();
            stream.Write(bs, 0, bs.Length);
            stream.Dispose();
            var response_temp = req.GetResponse();
            using (HttpWebResponse response = (HttpWebResponse)response_temp)
            {
                var e = response.ContentEncoding;
                int responseCode = (int)response.StatusCode;
                using (var reader = new StreamReader(response.GetResponseStream(), Encoding.GetEncoding("GB2312")))
                {
                    responseData = reader.ReadToEnd();

                    //JObject j = new JObject(responseData);
                }
            }

接收请求
var stream = Request.GetBufferedInputStream();
        var sReader = new StreamReader(stream);
        var body = sReader.ReadToEnd();

如果由form表单提交，则

var action = Request["action"] ;

 

转载于:https://www.cnblogs.com/yy2056/p/3893914.html