用Vector进行深层复制

一、Int3自Int2继承而来，将Int2的clone()当做Int3的clone()调用时，它会调用Object.clone()，判断出当前操作的是Int3，并复制Int3内的所有二进制位，只要没有新增需要克隆的句柄，对Object.clone()的一个调用就能完成所有必要的复制，可以总结出对Vector进行深层复制的先决条件：在克隆了Vector后，必须在其中遍历，并克隆由Vector指向的每个字段，为了对HashTable进行深层复制，也必须采取类似的处理，在克隆了对象以后，可以自由的改变他，而原来的那个对象不受影响。

import java.util.Enumeration;

import java.util.Vector;


class Int2 implements Cloneable{
private int i;
public Int2(int ii){
i = ii;
}
public void increment(){
i ++;
}
@Override
public String toString() {
return Integer.toString(i);
}
@Override
public Object clone() throws CloneNotSupportedException {
Object o = null;
o = super.clone();
return o;
}
}
class Int3 extends Int2{
private int j;
public Int3(int ii) {
super(ii);
}
}
public class AddingClone {
public static void main(String[] args) throws CloneNotSupportedException {
Int2 x = new Int2(10);
Int2 x2 = (Int2)x.clone();
x2.increment();
System.out.println("x = " + x + "  ,   x2 = " + x2);
Int3 x3 = new Int3(7);
Int3 x4 = (Int3)x3.clone();
System.out.println("x3 = " + x3 + "  ,  x4 = " + x4);
Vector v = new Vector();
for(int i=0; i<10; i++){
v.addElement(new Int2(i));
}
System.out.println("v = " + v);
Vector v2 = (Vector)v.clone();
for(int i=0; i v2.setElementAt(((Int2)v2.elementAt(i)).clone(), i);
}
for(Enumeration e = v2.elements(); e.hasMoreElements();){
((Int2)e.nextElement()).increment();
}
System.out.println("v: " + v);
System.out.println("v2: " + v2);
}

}

结果：

x = 10  ,   x2 = 11
x3 = 7  ,  x4 = 7
v = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
v: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
v2: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

二、通过序列化进行深层复制，对象在序列化后再撤销对它的序列化，那么实际经历的正是一个”克隆”过程，但花费时间远远大于克隆

import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.io.Serializable;


class Thing1 implements Serializable{}
class Thing2 implements Serializable{
Thing1 o1 = new Thing1();
}
class Thing3 implements Cloneable{
public Object clone() throws CloneNotSupportedException{
Object o = null;
o=super.clone();
return o;
}
}
class Thing4 implements Cloneable{
Thing3 o3 = new Thing3();
public Object clone() throws CloneNotSupportedException{
Thing4 o = null;
o = (Thing4)super.clone();
o.o3 = (Thing3)o3.clone();
return o;
}
}
public class Compete {
static final int SIZE = 5000;
public static void main(String[] args) throws IOException, ClassNotFoundException, CloneNotSupportedException {
Thing2[] a = new Thing2[SIZE];
for(int i=0; ia[i] = new Thing2();
}
Thing4[] b = new Thing4[SIZE];
for(int i=0; ib[i] = new Thing4();
}
long t1 = System.nanoTime();
ByteArrayOutputStream bout = new ByteArrayOutputStream();
ObjectOutputStream out = new ObjectOutputStream(bout);
for(int i=0; iout.writeObject(a[i]);
}
ObjectInputStream in = new ObjectInputStream(new ByteArrayInputStream(bout.toByteArray()));
Thing2[] c = new Thing2[SIZE];
for(int i=0; ic[i] = (Thing2)in.readObject();
}
long t2 = System.nanoTime();
System.out.println("Duplication via serialization : " + (t2-t1) + " nanoTime");
t1= System.nanoTime();
Thing4[] d = new Thing4[SIZE];
for(int i=0; id[i] = (Thing4)b[i].clone();
}
t2 = System.nanoTime();
System.out.println("Duplication via cloneing : " + (t2-t1) + " nanoTime");
}
}

结果：

Duplication via serialization : 34245163 Milliseconds
Duplication via cloneing : 1400956 Milliseconds