PAT考试乙级1057(C语言实现)

#include 
#include 
#include 
int main(){
    int num,i,len,sum=0,c1=0,c2=0;
    char a[10001];
    gets(a);
    len=strlen(a);
    for(i=0;iif('a'<=tolower(a[i])&&tolower(a[i])<='z'){//不要写成'a'<=tolower(a[i])<='z'
            sum=sum+tolower(a[i])-'a'+1;
        }
    }
    while(sum!=0){
        if(sum%2==0) c1++;
        else c2++;
        sum=sum/2;
    }
    printf("%d %d",c1,c2);
    return 0;
}