如何验证一个XML文件是否匹配XSD定义

如何验证XML文件是否匹配XSD

验证XML文件是否匹配一个XSD文件。

假设XSD文件定义为example02.xsd
输入XML文件为example02.xml，下面代码例子验证example02.xml是否匹配example02.xsd格式。

import java.io.File;
import java.io.IOException;
import java.net.URL;

import javax.xml.XMLConstants;
import javax.xml.transform.Source;

import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;

import org.xml.sax.SAXException;

public class ValidateTest {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        ValidateTest t = new ValidateTest ();
        try {
            t.validateXML("example02.xml", "example02.xsd");
        } catch (SAXException | IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    public void validateXML(String xml, String xsd) throws SAXException, IOException {
        SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);

        Schema schema = schemaFactory.newSchema(new File(xsd));
        // When if XSD is coming from a URL:
        //Schema schema2 = schemaFactory.newSchema(new URL("http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"));

        Source xmlFile = new StreamSource(new File(xml));
        Validator validator = schema.newValidator();
        validator.validate(xmlFile);
        System.out.println(xmlFile.getSystemId() + " is valid");
    }
}