Game of Taking Stones HDU - 5973 （威佐夫博弈+Java的高精度）

Game of Taking Stones

 HDU - 5973 

Two people face two piles of stones and make a game. They take turns to take stones. As game rules, there are two different methods of taking stones: One scheme is that you can take any number of stones in any one pile while the alternative is to take the same amount of stones at the same time in two piles. In the end, the first person taking all the stones is winner.Now,giving the initial number of two stones, can you win this game if you are the first to take stones and both sides have taken the best strategy?

Input

Input contains multiple sets of test data.Each test data occupies one line,containing two non-negative integers a andb,representing the number of two stones.a and b are not more than 10^100.

Output

For each test data,output answer on one line.1 means you are the winner,otherwise output 0.

Sample Input

2 1
8 4
4 7

Sample Output

0
1
0

import java.math.BigDecimal;
import java.util.Scanner;


public class Main {
	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		BigDecimal k, l, r, mid, two;
		l = new BigDecimal("2");
		r = new BigDecimal("3");
		two = new BigDecimal("2");
		mid = l;
		BigDecimal five = new BigDecimal("5");
		for (int i = 1; i <= 500; ++i) { // 不断二分来增加精度
			mid = l.add(r).divide(two);
			//System.out.println(mid);
			if (mid.multiply(mid).compareTo(five) < 0) {
				l = mid;
			} else {
				r = mid;
			}
		}
		//System.out.println(l);
		//System.out.println(mid);
		k = mid.add(new BigDecimal("1")).divide(two);
		//System.out.println(k);
		while (cin.hasNext()) {
			l = cin.nextBigDecimal();
			r = cin.nextBigDecimal();
			if (l.compareTo(r) > 0) {
				BigDecimal t = r;
				r = l;
				l = t;
			}
			mid = r.subtract(l);
			if (mid.multiply(k).toBigInteger().compareTo(l.toBigInteger())==0) {
				System.out.println("0");
			} else {
				System.out.println("1");
			}
			
		}
		
	}
}

博弈论之威佐夫博弈

C - Game of Taking Stones HDU - 5973 （威佐夫博弈+Java的高精度）