HDU 2199 Can you solve this equation? (二分)

Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4814    Accepted Submission(s): 2247

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

 

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

 

Sample Input

2

100

-4

 

 

Sample Output

1.6152

No solution!

 

 

Author

Redow

 

 

Recommend

lcy

 

 

#include<iostream>

#include<cstdio>

#include<cstring>



using namespace std;



const double eps=1e-10;



double y;



double f(double x){

    return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6-y;

}



int main(){



    //freopen("input.txt","r",stdin);



    int t;

    scanf("%d",&t);

    while(t--){

        scanf("%lf",&y);

        double l=0,r=100,mid;

        if(f(l)>eps || f(r)<eps){

            puts("No solution!");

            continue;

        }

        while(l+eps<=r){

            mid=(l+r)/2;

            if(f(mid)<eps)

                l=mid+eps;

            else

                r=mid-eps;

        }

        printf("%.4lf\n",l);

    }

    return 0;

}