一道关于数据按照一定规律分列的SQL解法

原题如下：


解答如下：

----第一题
select max(case
         when le = 1 then
          lv
       end) as c1,
       max(case
         when le = 2 then
          lv
       end) as c2,
       max(case
         when le = 0 then
          lv
       end) as c3
  from (select lv, mod(lv, 3) as le ,row_number()over(partition by mod(lv, 3)order by lv ) as rn
          from (select level as lv from dual connect by level <= 9))
          group by rn
 order by c1, c2, c3

---第二题
select max(case
         when le = 1 then
          lv
       end) as c1,
       max(case
         when le = 2 then
          lv
       end) as c2,
       max(case
         when le = 3 then
          lv
       end) as c3
  from (select lv, ceil(lv/ 4) as le ,row_number()over(partition by ceil(lv/4)order by lv ) as rn
          from (select level as lv from dual connect by level <= 9))
          group by rn
 order by c1, c2, c3

来自 “ ITPUB博客 ” ，链接：http://blog.itpub.net/29507357/viewspace-1225030/，如需转载，请注明出处，否则将追究法律责任。

转载于:http://blog.itpub.net/29507357/viewspace-1225030/