POJ 2406 kmp简单应用

Power Strings

Time Limit: 3000MS		Memory Limit: 65536K
Total Submissions: 29067		Accepted: 12143

Description

Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer is defined in the normal way: a^0 = "" (the empty string) and a^(n+1) = a*(a^n).

Input

Each test case is a line of input representing s, a string of printable characters. The length of s will be at least 1 and will not exceed 1 million characters. A line containing a period follows the last test case.

Output

For each s you should print the largest n such that s = a^n for some string a.

Sample Input

abcd
aaaa
ababab
.

Sample Output

1
4
3

已知一个字符串由多个子串重复若干次得到，求最大的重复次数，

思路：可以用kmp，也可以用后缀数组，后缀数组以后实现，kmp根据next数组可以得到循环节，进而可以得到重复次数。

代码：

/* ***********************************************
Author :xianxingwuguan
Created Time :2014-1-29 18:06:17
File Name :4.cpp
************************************************ */

#pragma comment(linker, "/STACK:102400000,102400000")
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include