FastJson和android.jar里面的org.json.JSONObject常规使用和google的Gson

FastJson：

1.先创建一个JavaBean对象

public class TestBean implements Serializable{
    private static final long serialVersionUID = -5992324248930299997L;
    private String name;
    private String age;

    public static long getSerialVersionUID() {
        return serialVersionUID;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getAge() {
        return age;
    }

    public void setAge(String age) {
        this.age = age;
    }

    @Override
    public String toString() {
        return "TestBean{" +
                "name='" + name + '\'' +
                ", age='" + age + '\'' +
                '}';
    }
}

2.1 将对象传给JSON，使用JSON.toJSONString()。将对象转成json的string格式

将对象转成json string
TestBean testBean = new TestBean();
testBean.setAge("12");
testBean.setName("Tom");
String json = JSON.toJSONString(testBean);//

2.2 将json string转成对象

TestBean testBean = JSON.parseObject(json, TestBean .class);

2.3 json string是json数组:[{"name":"Tom", "age":"1"},{name":"Jack", "age":"10"},{name":"Mike", "age":"11"}]

List testBeanList = JSON.parseArray(josnList, TestBean .class);

 

 

 

JSONObject

1.创建json string

JSONObject requestJSON = new JSONObject();
requestJSON.put("key", "123");
requestJSON.put("type", "test");  
requestJSON.put("content", "body"); 

String json = requestJSON.toString();

2.将json String提取出来

JSONObject jsonObject = new JSONObject(responseString2);
String name= jsonObject.optString("name");
String age= jsonObject.optString("age");

 

Gson

1.创建json string

Gson gson = new Gson;

gson.toJson(accountList)

2.json String 转 对象（这边注意对象需要继承Serializable接口，否则转换内容为空）

 PicResponse picResponse = gson.fromJson(result, PicResponse.class);