C++11多线程模拟售票

买火车票是大家春节回家最为关注的事情，我们就简单模拟一下火车票的售票系统

(为使程序简单，我们就抽出最简单的模型进行模拟)：有100张从北京到赣州的火车票，在6个窗口同时出售，保证系统的稳定性和数据的原子性。）

#include 
#include 
#include 
#include 
#include 
#include 
#include 
std::condition_variable cv;
std::mutex mutx;
int ticket = 100;
bool isrunning = true;
void consumer(int id)
{
	while (ticket > 0)
	{
		std::this_thread::sleep_for(std::chrono::milliseconds(100));
		std::lock_guard<std::mutex> lck(mutx);
		if(ticket > 0)
		{
			int x = (rand() % (10 - 1)) + 1;
			if (x > ticket)
				x = ticket;
			std::cout << "售票窗口[" << id << "]: ";
			ticket -= x;
			std::cout << "售出 " << x << "票" << std::endl;
			std::cout << "剩余 " << ticket << "票" << std::endl;
		}
		else
		{
			std::cout << "售票窗口[" << id << "]: ";
			std::cout << "票已经售完..." << std::endl;
		}
	}
}
int main()
{
	std::cout << "main thread:" << std::this_thread::get_id() << std::endl;
	std::cout << "总共票数为"  << ticket << std::endl;
	std::thread c[5];
	for (int i = 0; i < 5; i++)
		c[i] = std::thread(consumer, i+1);
	for (int i = 0; i < 5; i++)
		c[i].join();
	std::cout << "it's over..." << std::endl;
	return 0;
}