复数加减乘除实现（C++）

源码

（因为是昨晚写的，分析过程忘了，大家就直接看源码好了，反正还蛮简单的hhh）

#include 
using namespace std;
class complex
{
public:
	complex(int i = 0, int j = 0) :a(i), b(j) {}
	~complex() {};
	complex operator+(complex y)
	{
		complex temp;
		temp.a = a + y.a;
		temp.b = b + y.b;
		return temp;
	}
	complex operator-(complex y)
	{
		complex temp;
		temp.a = a - y.a;
		temp.b = b - y.b;
		return temp;
	}
	complex operator*(complex y)
	{
		complex temp;
		temp.a = a * y.a - b * y.b;
		temp.b = a * y.b + b * y.a;
		return temp;
	}
	complex operator/(complex y)
	{
		complex temp;
		temp.a = (a * y.a + b * y.b) / (y.a * y.a + y.b * y.b);
		temp.b = (b * y.a + a * y.b) / (y.a * y.a + y.b * y.b);
		return temp;
	}
	void getcomplex(float& aa, float& bb)
	{
		aa = a;
		bb = b;
	}

private:
	float a, b;
};
ostream& operator<<(ostream& os, complex& s)
{
	float a, b;
	s.getcomplex(a, b);
	os << a << "+" << b << "i";
	return os;
}
int main()
{
	complex x(1,1),y(1,1),z;
	z = x + y;
	cout << z << endl;
	z = x - y;
	cout << z << endl;
	z = x * y;
	cout << z << endl;
	z = x / y;
	cout << z << endl;
	return 0;
}