金山笔试题（2013）之LED数字显示

1、从键盘任意输入0-9之间的任意一个数字，显示数字的电子格式

 

import java.util.Scanner;
/*
A, B, C, D 表示数字的各二进制位
a, b, c, d, e, f, g 表示 LED 的各段，为 1 时该段显示，为 0 时该段不显示
 
      a
   #######
   #     # b
 f #  g  #
   #######
   #     # c
 e #     # 
   #######
      d
 
+---+---+---+---+---+  +---+---+---+---+---+---+---+
|   | A | B | C | D |  | a | b | c | d | e | f | g |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 0 | 0 | 0 | 0 | 0 |  | 1 | 1 | 1 | 1 | 1 | 1 | 0 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 1 | 0 | 0 | 0 | 1 |  | 0 | 1 | 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 2 | 0 | 0 | 1 | 0 |  | 1 | 1 | 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 3 | 0 | 0 | 1 | 1 |  | 1 | 1 | 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 4 | 0 | 1 | 0 | 0 |  | 0 | 1 | 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 5 | 0 | 1 | 0 | 1 |  | 1 | 0 | 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 6 | 0 | 1 | 1 | 0 |  | 1 | 0 | 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 7 | 0 | 1 | 1 | 1 |  | 1 | 1 | 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 8 | 1 | 0 | 0 | 0 |  | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
| 9 | 1 | 0 | 0 | 1 |  | 1 | 1 | 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+---+  +---+---+---+---+---+---+---+
*/
public class Num2LEDTest {
 
    public static void main(String[] args) {
        LED led = new LED();
        Scanner in=new Scanner(System.in);
        String LEDStr=in.nextLine();
        char[][] chss = led.getLED(LEDStr);
        LED.print(chss);
    }
}
 
class LED {
     
    /**
     * 每个 LED 的大小，可以进行调整
     */
    public final static int ROW = 7;
    public final static int COL = 7;
     
    /**
     * 每个 LED 的间隔
     */
    private final static int SEPARATOR = 1;
         
    private final static char FILL_CHAR = '#';
    private final static char SPACE_CHAR = ' ';
     
    /**
     * 工具方法，用于输出 LED
     * @param chs
     */
    public static void print(char[][] chs) {
        for(int i = 0; i < chs.length; i++) {
            for(int j = 0; j < chs[i].length; j++) {
                System.out.print(chs[i][j]);
            }
            System.out.println();
        }        
    }
     
    /**
     * 根据数字得到 LED 显示数组
     * @param num
     * @return
     */
    public char[][] getLED(String num) {
        char[] chs = num.toCharArray();
        char[][][] chsss = new char[chs.length][][];
        for(int i = 0; i < chs.length; i++) {
            chsss[i] = showLed(chs[i] - '0');
        }
        return putManyLed(chsss);
    }    
     
    /**
     * 将多个 LED 组成一排
     * @param chsss
     * @return
     */
    private char[][] putManyLed(char[][][] chsss) {
        if(chsss.length < 1) {
            throw new IllegalArgumentException("LED is NULL!");
        }
        if(chsss.length == 1) {
            return chsss[0];
        }
        char[][] chss = new char[ROW][chsss.length * (COL + SEPARATOR) - SEPARATOR];
        for(int i = 0; i < chsss.length; i++) {
            int m = i * (COL + SEPARATOR);
            for(int j = 0; j < chsss[i].length; j++) {                
                for(int k = 0; k < chsss[i][j].length; k++) {
                    chss[j][m + k] = chsss[i][j][k];
                }
            }
        }
        for(int i = 0; i < chss.length; i++) {
            for(int j = 0; j < chss[i].length; j++) {
                if(chss[i][j] != FILL_CHAR) {
                    chss[i][j] = SPACE_CHAR;
                }
            }
        }
        return chss;
    }
     
    /**
     * 
     * @param num
     * @return
     */
    private char[][] showLed(int num) {
        boolean[] b = getLed(num);
        char[][] chs = new char[ROW][COL];
        if(b[0])
            for(int i = 0; i < COL; i++) chs[0][i] = FILL_CHAR; 
        if(b[1])
            for(int i = 0; i <= ROW / 2; i++) chs[i][COL - 1] = FILL_CHAR;
        if(b[2])
            for(int i = ROW / 2; i < ROW; i++) chs[i][COL - 1] = FILL_CHAR;
        if(b[3])
            for(int i = 0; i < COL; i++) chs[ROW - 1][i] = FILL_CHAR;
        if(b[4])
            for(int i = ROW / 2; i < ROW; i++) chs[i][0] = FILL_CHAR;
        if(b[5])
            for(int i = 0; i <= ROW /2; i++) chs[i][0] = FILL_CHAR;
        if(b[6])
            for(int i = 0; i < COL; i++) chs[ROW / 2][i] = FILL_CHAR;        
        return chs;
    }
     
    /**
     * 译码器
     * 
     *       0
     *    #######
     *    #     # 1
     *  5 #  6  #
     *    #######
     *    #     #
     *  4 #     # 2
     *    #######
     *       3
     * 
     * 0 表示 leds[0]，若为 true 表示该 LED 显示，否则不显示
     * 
     * @param num
     * @return
     */
    private boolean[] getLed(int num) {        
        boolean a = (num & 8) >>> 3 == 1;
        boolean b = (num & 4) >>> 2 == 1;
        boolean c = (num & 2) >>> 1 == 1;
        boolean d = (num & 1) == 1;
        boolean[] leds = new boolean[7];
        leds[0] = (!a & !b & !c & d) | (b & !d);
        leds[1] = (b & !c & d) | (b & c & !d);
        leds[2] = !b & c & !d;
        leds[3] = (b & !c & !d) | (!b & !c & d) | (b & c & d);
        leds[4] = d | (b & !c);
        leds[5] = (c & d) | (!b & c) | (!a & !b & d);
        leds[6] = (!a & !b & !c) | (b & c & d);
        for(int i = 0; i < 7; i++) {
            leds[i] = !leds[i];
        }
        return leds;
    }
}

运行截图

 

 

2、L"string"转换成_X("string")怎么实现,可利用一些文本编辑的工具。

此题求网友给出答案

 

3、有head1.h,head2.h,src1.cpp,src2.cpp,main.cpp怎么整合生成可执行文件xxx.exe或xxx,请写出具体步骤和编译执行过程。

我是用makefile加上gcc做的：

xxx: src1.o src2.o main.cpp
gcc xxx -o main.cpp
src1.o : head2.h src2.cpp
gcc -c src2.cpp -o src2.o
src1.o : head1.h src1.cpp
gcc -c src1.cpp -o src1.o