jpa like模糊查询

	一楼问：
Hi, I'm trying to use the LIKE statement with JPA. What I want to do is get all the items that have a name that matchs the keyword 'og' for example ('Dog', 'Big dog'...). If I write that : query = em.createQuery("SELECT i FROM Item i WHERE i.name LIKE :keyword"); query.setParameter("keyword", keyword); That will take the items that have the exact keword (in my example only 'og' will appear). I've tried to use the wildcards % but id doesn't work : query = em.createQuery("SELECT i FROM Item i WHERE i.name LIKE '%:keyword%'"); query = em.createQuery("SELECT i FROM Item i WHERE i.name LIKE %:keyword%"); Does anybody knows how to use the LIKE statement with wildcards ? And by the way, is there a way to ignore the case of my keyword ('og' or 'OG' should give the same result). Thanks, Antonio Goncalves

二楼：       Hello Antonio, Can you not use query = em.createQuery("SELECT i FROM Item i WHERE UPPER(i.name) LIKE UPPER(:keyword)"); query.setParameter("keyword","%"keyword"%"); query.getResultList(); Best Regards, Chris

三楼：   Hi Chris. It doesn't work with the UPPER keyword. Here is the error that I've got : Caused by: Exception [TOPLINK-8025] (Oracle TopLink Essentials - 2006.4 (Build 060412)): oracle.toplink.essentials.exceptions.EJBQLException Exception Description: Syntax error parsing the query [SELECT i FROM Item i WHERE UPPER(i.name) LIKE UPPER(:keyword) ORDER BY i.name], unexpected token [LIKE]. |#] Any idea ? Otherwise, the wildcard works fine : query = em.createQuery("SELECT i FROM Item i WHERE i.name LIKE :keyword"); query.setParameter("keyword","%"keyword"%"); query.getResultList();

四楼：       Hello, Sorry, looks like i was wrong on the UPPER(:keword) portion. The spec states: string_expression [NOT] LIKE pattern_value [ESCAPE escape_character] "The pattern_value is a string literal or a string-valued input parameter" So you will have to call toUpperCase() on the string you pass into the query ie: query.setParameter("keyword","%"keyword.toUpperCase()"%"); Best Regards, Chris

最终写法：     Thanks, it works fine like that query = em.createQuery("SELECT i FROM Item i WHERE UPPER(i.name) LIKE :keyword ORDER BY i.name"); query.setParameter("keyword", "%" + keyword.toUpperCase() + "%"); Antonio

 

我的

错误写法：sql.append(" and s.idCard like %?% ");

paraml.add(stuff.getIdCard().trim());

正确应该是：

   sql.append(" and s.idCard like ? ");
   
   paraml.add("%"+stuff.getIdCard().trim()+"%");
  

转自：http://forums.oracle.com/forums/thread.jspa?threadID=423742