Java web 用户注册界面(Ajax)

实验内容及步骤

开发一个用户注册界面,要求: 用户名基于 Ajax 检测是否重复,年龄需用 JavaScript 检查格式是否正确

代码如下:

FORM.jsp(jsp页面)

<%@ page language="java" contentType="text/html; charset=gb2312"%>


表单验证





请输入用户名:

请输入年龄 :

Formcheck.java(检测的servlet)

package servlets;

import java.io.IOException;
import java.io.PrintWriter;
import java.util.Arrays;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class FormCheck extends HttpServlet {
	/**
	 * 
	 */
	private static final long serialVersionUID = 1L;

	protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		response.setContentType("text/html;charset=GB18030");
		PrintWriter out = response.getWriter();
		request.setCharacterEncoding("GB18030");
		//String[] userList={"1","2","3","4"};
		String userid = request.getParameter("userid");
		//Arrays.sort(userList);									//对数组排序	
		//int result=Arrays.binarySearch(userList,userid);				//搜索数组
		if("2".equals(userid)){
			out.println("很抱歉,该用户名已经被注册!");			//输出检测结果
		}
		else {
			out.println("恭喜您,该用户名没有被注册!");
		}
	}
}

web.xml(配置文件)




formcheck
servlets.FormCheck


formcheck
/formcheck

如有错误请指出。

经运行无误。

你可能感兴趣的:(Java web 用户注册界面(Ajax))