PAT (Advanced Level) Practice 1021~1030

1021

---

1022

---

1023

---

1024

---

1025 PAT Ranking

Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.

Input Specification:
Each input file contains one test case. For each case, the first line contains a positive number $N(\le 100)$, the number of test locations. Then N ranklists follow, each starts with a line containing a positive integer #K (≤300)#, the number of testees, and then K lines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.

Output Specification:
For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:

registration_number final_rank location_number local_rank
The locations are numbered from 1 to N. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.

Sample Input:
2
5
1234567890001 95
1234567890005 100
1234567890003 95
1234567890002 77
1234567890004 85
4
1234567890013 65
1234567890011 25
1234567890014 100
1234567890012 85

Sample Output:
9
1234567890005 1 1 1
1234567890014 1 2 1
1234567890001 3 1 2
1234567890003 3 1 2
1234567890004 5 1 4
1234567890012 5 2 2
1234567890002 7 1 5
1234567890013 8 2 3
1234567890011 9 2 4

Note
简单的排序，没什么需要记录的。

#include 
#include 
#include 
using namespace std;

struct student
{
    char number[15]; // 准考证号
    int score; // 分数
    int location; // 考场号
    int local_rank; // 考场内排名
} stu[30010]; // 最多三万名学生

bool cmp(student a, student b) // 比较函数，分数降序排列，分数相等时准考证号升序排列
{
    if (a.score != b.score)
        return a.score > b.score;
    else
        return strcmp(a.number, b.number) < 0;
}

int main()
{
    int N, K, num = 0; // num为总考生数
    cin >> N;
    for (int i = 1; i <= N; ++i)
    {
        cin >> K; // 该考场内人数
        for (int j = 0; j < K; ++j) // 输入k个受测者信息
        {
            cin >> stu[num].number >> stu[num].score; // 输入注册号和分数
            stu[num++].location = i; // 记录考场号，同时考生数+1
        }
        sort(stu + num - K, stu + num, cmp); // 将该考场的考生排序

        stu[num - K].local_rank = 1; // 将该考场第一名的考场排名记为1
        for (int j = num - K + 1; j < num; ++j)
        {
            if (stu[j].score == stu[j - 1].score) // 考场
                stu[j].local_rank = stu[j - 1].local_rank;
            else
                stu[j].local_rank = j + 1 - num + K; // 不相等就为下标 + 1
        }
    }
    sort(stu, stu + num, cmp); // 所有数据输入完后重新排列
    cout << num << endl; // 输出总考生数
    int r = 1;
    for (int i = 0; i < num; ++i)
    {
        if (i > 0 && stu[i].score != stu[i - 1].score)
            r = i + 1;
        cout << stu[i].number << ' ' << r << ' ' << stu[i].location << ' ' << stu[i].local_rank << endl;
    }

    return 0;
}

---

1026

---

1027

---

1028

---

1029

---

1030

---

一定要自己写一遍哦~~~