【笨方法学PAT】1132 Cut Integer （20 分）

一、题目

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2​31​​). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample Output:

Yes
No
No

二、题目大意

一个整数从中间分成两个整数，原来的整数是否能整出两个新的整数。

三、考点

string

四、注意

1、b*c==0判断，否则浮点错误；

2、substr的用法，substr(n1,n2)，从n1开始的n2个字符。

五、代码

#include
#include
using namespace std;
int main() {
	//read
	int n;
	cin >> n;

	//solve
	while (n--) {
		long long int a;
		cin >> a;
		string s =to_string(a);
		int b = stoi(s.substr(0, s.length() / 2));
		int c = stoi(s.substr(s.length() / 2));
		if (b*c != 0 && a % (b*c) == 0)
			cout << "Yes" << endl;
		else
			cout << "No" << endl;
	}

	system("pause");
	return 0;
}