poj 2629 Common permutation

Common permutation

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 5059		Accepted: 1519

Description

Given two strings of lowercase letters, a and b, print the longest string x of lowercase letters such that there is a permutation of x that is a subsequence of a and there is a permutation of x that is a subsequence of b.

Input

Input consists of pairs of lines. The first line of a pair contains a and the second contains b. Each string is on a separate line and consists of at most 1,000 lowercase letters.

Output

For each subsequent pair of input lines, output a line containing x. If several x satisfy the criteria above, choose the first one in alphabetical order.

Sample Input

pretty
women
walking
down
the
street

Sample Output

e
nw
et

#include
#include
using namespace std;

int comp(char &a,char &b)
{
return a}

int main()
{
char a[1001];
char b[1001];
int i,j;
int lena,lenb;
int pos;
while(gets(a) && gets(b))
    {
        lena=strlen(a);
        lenb=strlen(b);
        sort(a,a+lena,comp);
        sort(b,b+lenb,comp);
        pos=-1;
for(i=0;i        {
for(j=pos+1;j            {
if(a[i]==b[j])
                {
                    pos=j;
                    cout<break;
                }
            }
        }
        cout<    }
return 0;
}

转载于:https://www.cnblogs.com/w0w0/archive/2011/11/22/2258621.html