c语言用递归的方法实现1！+2！+3！+4！+.....+n！=？阶乘之和

#include "stdafx.h"
#include 

int getmul(int n){//递归求阶乘
   int sum;
   int temp = 1;
   if(n<=0){ 
        printf("输入的数据错误，不能小于0！\n");
        return -1;
    }else{
          if(n ==1 ){ sum = 1; return sum;}
           else {
               sum =n * getmul(n-1); 
               return sum;
          }
     }
}

int getSum(int n){//递归求和
      int sum;
      if(n==0){
           sum =0;
      }else{
           sum = getmul(n) + getSum(n-1);
     }
      return sum;
}

void print(int n){//打印
   for(int i=1; i <=n; i ++){
      if(i==n) printf("%d!=",i);
      else printf("%d!+",i);
   }
}

int main(int argc, char* argv[])
{
   int a = 10;//此为求1到10的阶乘只和
   print(a);
   printf("%d\n",getSum(a));//调用
   return 0;
}