调整Django菜单顺序

不修改Django源码让admin中的Model列表按注册顺序显示

from django.contrib import admin
from django.utils.text import capfirst
from django.utils.datastructures import OrderedDict


def find_model_index(name):
    count = 0
    for model, model_admin in admin.site._registry.items():
        if capfirst(model._meta.verbose_name_plural) == name:
            return count
        else:
            count += 1
    return count


def index_decorator(func):
    def inner(*args, **kwargs):
        templateresponse = func(*args, **kwargs)
        for app in templateresponse.context_data['app_list']:
            app['models'].sort(key=lambda x: find_model_index(x['name']))
        return templateresponse

    return inner


# registry = OrderedDict()
# registry.update(admin.site._registry)
# admin.site._registry = registry
admin.site.index = index_decorator(admin.site.index)
admin.site.app_index = index_decorator(admin.site.app_index)

由于我使用的是Python3.6，Django2.0，所以字典类型已变成有序的了，就有了上述注释掉的三行代码。

但是上述代码不完善：只对app内部的各个model，根据注册顺序进行了排序。而没有对各个app做排序。

查看源代码，Django是根据字典序排列app的。并不能够自定义。

由于app没有字段来控制排序规则，所以需要加一个：

from django.apps import AppConfig


class DemoConfig(AppConfig):
    name = 'demo'
    verbose_name = 'Demo'
    main_menu_index = 0

通过main_menu_index来排序。完整代码如下：

from django.apps import apps
from django.contrib import admin
from django.utils.text import capfirst

def find_app_index(app_label):
    app = apps.get_app_config(app_label)
    main_menu_index = getattr(app, 'main_menu_index', 9999)
    return main_menu_index


def find_model_index(name):
    count = 0
    for model, model_admin in admin.site._registry.items():
        if capfirst(model._meta.verbose_name_plural) == name:
            return count
        else:
            count += 1
    return count


def index_decorator(func):
    def inner(*args, **kwargs):
        templateresponse = func(*args, **kwargs)
        app_list = templateresponse.context_data['app_list']
        app_list.sort(key=lambda r: find_app_index(r['app_label']))
        for app in app_list:
            app['models'].sort(key=lambda x: find_model_index(x['name']))
        return templateresponse

    return inner


# registry = OrderedDict()
# registry.update(admin.site._registry)
# admin.site._registry = registry
admin.site.index = index_decorator(admin.site.index)
admin.site.app_index = index_decorator(admin.site.app_index)