斐波那契数的实现

#include  < stdlib.h >

int  main( int  argc, char  argv[])
{
     int  n;
     int  fn;
     int  fn2;
     int  fn1;
     int  i;
    
    printf( " 请输入数列项数==>  " );
    scanf( " %d " , & n);
     if (n  <=   1 )
    {
        printf( " [%d]\n " ,n);
    }
     else
    {
        fn2  = 0 ;
        fn1 = 1 ;
        printf( " [0][1] " );
         for (i = 2 ;i <= n;i ++ )
        {
            fn  =  fn2 + fn1;
            printf( " [%d] " ,fn);
            fn2 = fn1;
            fn1 = fn;
        }
        printf( " \n " );
    }
    
}

本然用我自创的CC语法实现一下，但还是各种原因先放着吧。