django2.2 配置urls

项目名下：

urls.py

from django.contrib import admin
from django.urls import path,include

urlpatterns = [
    path('admin/', admin.site.urls),
    path('',include('booktest.urls')),
]

APP下：

urls.py

from django.contrib import admin
from django.urls import path
from . import views

urlpatterns = [
    # path('admin/', admin.site.urls),
    path('index/', views.index)
]

然后开启服务：访问以下地址

http://127.0.0.1:8000/index/