leetcode069-python x的平方根

Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.

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解题要点：

1.直接使用python的sqrt函数

import math as mt
class Solution:
    def mySqrt(self, x):
        """
        :type x: int
        :rtype: int
        """
        c = mt.sqrt(x)
        return int(c)