Java中返回值的注意事项

阅读更多
在看Core Java过程中发现了一个许久以来未曾注意的地方,就是返回值,Java里虽然没有指针,但是一些参数传递都是通过指针完成的。如下面的Employee类,
class Employee
{
   public Employee(String n, double s, int year, int month, int day)
   {
      name = n;
      salary = s;
      GregorianCalendar calendar = new GregorianCalendar(year, month - 1, day);
         // GregorianCalendar uses 0 for January
      hireDay = calendar.getTime();
   }

   public String getName()
   {
      return name;
   }
   public double getSalary()
   {
      return salary;
   }

   public Date getHireDay()
  {
      return hireDay;
   }
   public void raiseSalary(double byPercent)
   {
      double raise = salary * byPercent / 100;
      salary += raise;
   }

   private String name;
   private double salary;
   private Date hireDay;
}

假如创建一个对象
	   Employee ben=new Employee("ben",10000,2014,4,1);
	   Date d=ben.getHireDay();
	   MyLog.a(d.toString());
	   double tenYearsInMilliSeconds = 10 * 365.25 * 24 * 60 * 60 * 1000;
	   d.setTime(d.getTime() - (long) tenYearsInMilliSeconds);
	   MyLog.a(ben.getHireDay().toString());

显示结果如下:
Tue Apr 01 00:00:00 CST 2014
Wed Mar 31 12:00:00 CST 2004

这里就出现问题了,再次调用 ben.getHireDay()查看时发现已经改变了,原因就是返回值实际上是一个指针,当对d做操作时,实际上是改hireDay的内存,那么原有的对象就改变了,这样编程语法上不会有什么问题,但实际上谬以千里,还需注意。
正确写法如下:
public Date getHireDay()
   {
      return (Date) hireDay.clone();
   }


再次运行,没有问题:
Tue Apr 01 00:00:00 CST 2014
Tue Apr 01 00:00:00 CST 2014


同时对String和Double做了测试:
没有这个问题。

你可能感兴趣的:(java)