SpringDataJpa使用原生sql查询之后返回map类型 有key有value
有问题的写法
// 使用List接收原生sql查询后返回的数据
@Query(value = "select a.id as uid,a.name,a.token,b.id as aid,b.address,b.door from user a left join address b on a.id = b.uid where a.is_delete = 0 and a.id = :userId order by b.id desc", nativeQuery = true)
List getAddressAndUserInfo(@Param("userId") String userId);
通常使用上述方式接收返回数据的朋友比较多 此时返回的数据是列表 不存在key value形式
返回示例
{
"code": "200",
"message": "SUCCESS",
"result": [
[
"U00000000001",
"小哥",
"",
8,
"哈哈",
"8栋223房间"
],
[
"U00000000001",
"小哥",
"",
7,
"哈哈",
"7栋223房间"
],
[
"U00000000001",
"小哥",
"",
6,
"哈哈",
"6栋223房间"
],
[
"U00000000001",
"小哥",
"",
5,
"哈哈",
"5栋223房间"
],
[
"U00000000001",
"小哥",
"",
4,
"哈哈",
"4栋223房间"
],
[
"U00000000001",
"小哥",
"",
3,
"哈哈",
"3栋223房间"
],
[
"U00000000001",
"小哥",
"",
2,
"哈哈",
"2栋223房间"
],
[
"U00000000001",
"小哥",
"",
1,
"哈哈",
"2栋223房间"
]
]
}
正常写法
// 使用List返回示例
{
"code": "200",
"message": "SUCCESS",
"result": [
{
"uid": "U00000000001",
"door": "8栋223房间",
"name": "小哥",
"aid": "8",
"address": "哈哈",
"token": ""
},
{
"uid": "U00000000001",
"door": "7栋223房间",
"name": "小哥",
"address": "哈哈",
"aid": "7",
"token": ""
},
{
"uid": "U00000000001",
"name": "小哥",
"door": "6栋223房间",
"address": "哈哈",
"aid": "6",
"token": ""
},
{
"uid": "U00000000001",
"name": "小哥",
"door": "5栋223房间",
"aid": "5",
"address": "哈哈",
"token": ""
},
{
"uid": "U00000000001",
"name": "小哥",
"aid": "4",
"address": "哈哈",
"door": "4栋223房间",
"token": ""
},
{
"uid": "U00000000001",
"name": "小哥",
"address": "哈哈",
"door": "3栋223房间",
"aid": "3",
"token": ""
},
{
"uid": "U00000000001",
"name": "小哥",
"address": "哈哈",
"door": "2栋223房间",
"token": "",
"aid": "2"
},
{
"uid": "U00000000001",
"name": "小哥",
"address": "哈哈",
"aid": "1",
"door": "2栋223房间",
"token": ""
}
]
}